In such Problems there may be three situations:
i. Age some years ago
ii. Present age
iii. Age some year hence
Now we are going to solve some questions:
Age some years ago:
Ex.1 Ram is a 40-year-old Mohan who is 60 years old. How many years ago was the ratio of their ages of 3:5.
Sol. (40-x)/ 60-x = 3/5
X=10
Present age:
Ex.2 The ratio of the present age of Rahul and Vikram is 2:1. The ratio of their age after 30 years will be 7:6. What is the present age of Rahul?
Sol. Conventional Method.
Let the present age of Rahul and Ram be 2x and x.
After 30 year
(2x+30)/(x+30) = 7/6
12x +180 = 7x + 210
12x-7x = 210-180
5x = 30
X= 6
Rahul’s present age is 2 *6 = 12
Short trick
Sol. Conventional Method.
Let the present age of Rahul and Ram be 2x and x.
After 30 year
(2x+30)/(x+30) = 7/6
12x +180 = 7x + 210
12x-7x = 210-180
5x = 30
X= 6
Rahul’s present age is 2 *6 = 12
Short trick
R0 : V0 = 2:1
R30: V30 = 7:6
Difference between R0 and R30 = 7- 2= 5
Difference between V0 and V30 = 6-1 = 5
This means, 5 Ratio = 30 years
1 ratio = 6
The present age of Rahul and Vikram is = 6*2: 6*1 = 12 and 6 years
Age some year hence:
Ex .3 Neeraj is as younger than Gopal as he is older than Deepak. If the sum of the ages of Gopal and Deepak is 58 yrs. What is Neeraj's age?
Sol. G-D = N-d
G+D = 2N
58 =2N
N= 29 years Ans.
R30: V30 = 7:6
Difference between R0 and R30 = 7- 2= 5
Difference between V0 and V30 = 6-1 = 5
This means, 5 Ratio = 30 years
1 ratio = 6
The present age of Rahul and Vikram is = 6*2: 6*1 = 12 and 6 years
Age some year hence:
Ex .3 Neeraj is as younger than Gopal as he is older than Deepak. If the sum of the ages of Gopal and Deepak is 58 yrs. What is Neeraj's age?
Sol. G-D = N-d
G+D = 2N
58 =2N
N= 29 years Ans.
Type 1.
If t1 yrs earlier the father's age was x times that of his son. At present, the father's age is y times that of his son. What are the present ages of the son and the father?
then,
son's age = t1(x-1)/(x-y)
Ex. 4 The age of the father 3 years ago was 7 times his son. At present fathers, age is five times that of his son. What are the present ages of the father and the son?
Sol 1 Let the present age of son = x yrs
3 year ago,
7(x-3) = 5x-3
7x-21 = 5x-3
2x= 18
x= 9 yrs
Therefore son's age = 9 yrs
Father's age = 45
Short trick:
Method 1.
Son's age = 3(7-1)/ (7-5 ) = 9 yrs
Fathers's age = 9*5 = 45 yrs.
Method 2.
S: F
3yrs 1:7 , 1-7 = 6 Difference between ratio
Present 1:5 ,1-5 = 4 Difference between ratio
then,
3yrs (1:7) *4 = 4: 28
present (1:5) *6 = 6: 30
2 ratio = 3 yerars
1 = 3/2 years
Present age of son and father = (6 : 30) * 3/2= 9 : 45
The present age of son = 9
The present age of father = 45
Type 2.
The present age of the father is y times the age of his son. T2 years hence, the father's age becomes z times the age of his son. What are the present ages of the father and his son?
Son's age = (z-1)T2/(y-z)
Ex.5. At present, The age of the father is five times the age of his son, Three years hence, the father's age would be four times that of his son. find the present ages of the Father and the son.
If t1 yrs earlier the father's age was x times that of his son. At present, the father's age is y times that of his son. What are the present ages of the son and the father?
then,
son's age = t1(x-1)/(x-y)
Ex. 4 The age of the father 3 years ago was 7 times his son. At present fathers, age is five times that of his son. What are the present ages of the father and the son?
Sol 1 Let the present age of son = x yrs
3 year ago,
7(x-3) = 5x-3
7x-21 = 5x-3
2x= 18
x= 9 yrs
Therefore son's age = 9 yrs
Father's age = 45
Short trick:
Method 1.
Son's age = 3(7-1)/ (7-5 ) = 9 yrs
Fathers's age = 9*5 = 45 yrs.
Method 2.
S: F
3yrs 1:7 , 1-7 = 6 Difference between ratio
Present 1:5 ,1-5 = 4 Difference between ratio
then,
3yrs (1:7) *4 = 4: 28
present (1:5) *6 = 6: 30
2 ratio = 3 yerars
1 = 3/2 years
Present age of son and father = (6 : 30) * 3/2= 9 : 45
The present age of son = 9
The present age of father = 45
Type 2.
The present age of the father is y times the age of his son. T2 years hence, the father's age becomes z times the age of his son. What are the present ages of the father and his son?
Son's age = (z-1)T2/(y-z)
Ex.5. At present, The age of the father is five times the age of his son, Three years hence, the father's age would be four times that of his son. find the present ages of the Father and the son.
Sol. Let the present age of son= x
Then, the present age of father = 5x
3 years hence,
4(x+3) = 5x+3
x = 9 yrs
son's age =9 years
Father's age =45
Shortcut
Then, the present age of father = 5x
3 years hence,
4(x+3) = 5x+3
x = 9 yrs
son's age =9 years
Father's age =45
Shortcut
Method 1.
Son's age = (4-1)*3/(5-4) = 9 years
Father's age = 9*5 = 45 years
Method 2.
S: F
Father's age = 9*5 = 45 years
Method 2.
S: F
Present age (1:5) *3 = 3:15
3 year hence (1:4) *4 = 4:16
1 ratio = 3
The present age of father and son = (3:15)*3 = 9 years and 45 years.
3 year hence (1:4) *4 = 4:16
1 ratio = 3
The present age of father and son = (3:15)*3 = 9 years and 45 years.
Type 3.
t1 years earlier, the age of the father was x times the age of his son. t2 years hence, the age of the father becomes z times the age of his son. What are the present ages of the son and the father?
Son's age =t2(z-1) +t1(x-1)/ (x-z)
Ex.6 Three years earlier, the father was 7 times as old as his son. Three years hence, the father's age would be four times that of his son. What are the present ages of the father and his son?
Sol. Let the present age of son = x years
The present age of father = years
3 years earlier, 7(x-3)= y-3
3year hence, 4(x+3)= y+3
4x+12= y+3
son solving equation we got
son's age = 9 years
Father's age = 45 years
Shortcut
Method 1.
Son's age = 3(4-1)+ 3(7-1)/ (7-4) =9 years
Fathers' age = 45 years
Method 2.
S: F
Age 3 year ago (1:7)*3= 3:21
Present age
Age 3 year hence (1:4)*6= 6:24
3 ratio = 6 years
1 ratio = 2 years
.5 ratio = 1 year
Age 3 year ago (1:7)*3= 3 :21
Present age 4.5:22.5
Age 3 year hence (1:4)*6= 6 :24
1 ratio = 2 years
Present age of son and father = (4.5 : 22.5)*2 = 9 years and 45 years
t1 years earlier, the age of the father was x times the age of his son. t2 years hence, the age of the father becomes z times the age of his son. What are the present ages of the son and the father?
Son's age =t2(z-1) +t1(x-1)/ (x-z)
Ex.6 Three years earlier, the father was 7 times as old as his son. Three years hence, the father's age would be four times that of his son. What are the present ages of the father and his son?
Sol. Let the present age of son = x years
The present age of father = years
3 years earlier, 7(x-3)= y-3
3year hence, 4(x+3)= y+3
4x+12= y+3
son solving equation we got
son's age = 9 years
Father's age = 45 years
Shortcut
Method 1.
Son's age = 3(4-1)+ 3(7-1)/ (7-4) =9 years
Fathers' age = 45 years
Method 2.
S: F
Age 3 year ago (1:7)*3= 3:21
Present age
Age 3 year hence (1:4)*6= 6:24
3 ratio = 6 years
1 ratio = 2 years
.5 ratio = 1 year
Age 3 year ago (1:7)*3= 3 :21
Present age 4.5:22.5
Age 3 year hence (1:4)*6= 6 :24
1 ratio = 2 years
Present age of son and father = (4.5 : 22.5)*2 = 9 years and 45 years
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