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    Problems based on age Solved with shortcut methods

    Problems based on Age
    Problems based on age Solved with shortcut methods

    Equation Problems of Age are part of the quantitative aptitude section. In the equation problems of age, the questions are such that they result in equations. These equations could become either linear or non-linear and they will have solutions that will represent the age of the people in the question. In the following sections, we will some examples of these problems and also learn about the various shortcuts that we can use to solve them.

    In such Problems there may be three situations:
    i. Age some years ago
    ii. Present age
    iii. Age some year hence

    Now we are going to solve some questions:

    Age some years ago:

    Ex.1 Ram is a 40-year-old Mohan who is 60 years old. How many years ago was the ratio of their ages of 3:5.
    Sol. (40-x)/ 60-x = 3/5
    X=10

    Present age:

    Ex.2 The ratio of the present age of Rahul and Vikram is 2:1. The ratio of their age after 30 years will be 7:6. What is the present age of Rahul?
    Sol. Conventional Method.
    Let the present age of Rahul and Ram be 2x and x.
    After 30 year
    (2x+30)/(x+30) = 7/6
    12x +180 = 7x + 210
    12x-7x = 210-180
    5x = 30
    X= 6
    Rahul’s present age is 2 *6 = 12

    Short trick

    R0 : V0 = 2:1
    R30: V30 = 7:6
    Difference between R0 and R30 = 7- 2= 5
    Difference between V0 and V30 = 6-1 = 5
    This means, 5 Ratio = 30 years
    1 ratio = 6
    The present age of Rahul and Vikram is = 6*2: 6*1 = 12 and 6 years

    Age some year hence:

    Ex .3 Neeraj is as younger than Gopal as he is older than Deepak. If the sum of the ages of Gopal and Deepak is 58 yrs. What is Neeraj's age?
    Sol. G-D = N-d
    G+D = 2N
    58 =2N
    N= 29 years Ans.

    Type 1.

    If t1 yrs earlier the father's age was x times that of his son. At present, the father's age is y times that of his son. What are the present ages of the son and the father?
    then,
    son's age = t1(x-1)/(x-y)

     
    Ex. 4 The age of the father 3 years ago was 7 times his son. At present fathers, age is five times that of his son. What are the present ages of the father and the son?
    Sol 1 Let the present age of son = x yrs
    3 year ago,
    7(x-3) = 5x-3
    7x-21 = 5x-3
    2x= 18
    x= 9 yrs
    Therefore son's age = 9 yrs
    Father's age = 45

    Short trick:
    Method 1.
     Son's age = 3(7-1)/ (7-5 ) = 9 yrs
     Fathers's age = 9*5 = 45 yrs.

    Method 2.
                  S: F 
    3yrs        1:7 , 1-7 = 6 Difference between ratio
    Present  1:5  ,1-5 = 4 Difference between ratio
    then,

    3yrs        (1:7) *4 =  4: 28
    present  (1:5) *6 =  6: 30

    2 ratio = 3 yerars
    1 = 3/2 years
    Present age of son and father = (6 : 30) * 3/2=  9 : 45
    The present age of son = 9
    The present age of father = 45

    Type 2.

    The present age of the father is y times the age of his son. T2 years hence, the father's age becomes z times the age of his son. What are the present ages of the father and his son?

    Son's age = (z-1)T2/(y-z)
    Ex.5. At present, The age of the father is five times the age of his son, Three years hence, the father's age would be four times that of his son. find the present ages of the Father and the son.
    Sol. Let the present age of son= x
    Then, the present age of father = 5x
    3 years hence,
    4(x+3) = 5x+3
    x = 9 yrs
    son's age =9 years
    Father's age =45

    Shortcut 

    Method 1.
    Son's age = (4-1)*3/(5-4) = 9 years
    Father's age = 9*5 = 45 years

    Method 2.

                            S: F
    Present  age   (1:5) *3 = 3:15
    3 year hence  (1:4) *4 = 4:16

    1 ratio = 3

    The present age of father and son = (3:15)*3 = 9 years and 45 years.

    Type 3.

    t1 years earlier, the age of the father was x times the age of his son. t2 years hence, the age of the father becomes z times the age of his son. What are the present ages of the son and the father?

    Son's age =t2(z-1) +t1(x-1)/ (x-z)

    Ex.6 Three years earlier, the father was 7 times as old as his son. Three years hence, the father's age would be four times that of his son. What are the present ages of the father and his son?
    Sol. Let the present age of son = x years
    The present age of father = years
    3 years earlier, 7(x-3)= y-3
    3year hence, 4(x+3)= y+3
    4x+12= y+3
     son solving equation we got
    son's age = 9 years
    Father's age =  45 years

    Shortcut

    Method 1.
    Son's age = 3(4-1)+ 3(7-1)/ (7-4) =9 years
    Fathers' age = 45 years

    Method 2.

    S: F
    Age 3 year ago      (1:7)*3= 3:21
    Present age      
    Age 3 year hence  (1:4)*6= 6:24

    3 ratio = 6 years
    1 ratio = 2 years
    .5 ratio = 1 year

    Age 3 year ago      (1:7)*3= 3   :21
    Present age                           4.5:22.5 
    Age 3 year hence  (1:4)*6= 6   :24
    1 ratio = 2 years

     Present age of son and father = (4.5 : 22.5)*2 = 9 years and 45 years



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