Average of all observation is = (n1 a1 + n2 a2 + ……)/ (n1+n2)
Average of rest of the observation = (ma-nb)/ m-n
Ex.1 If the average of m numbers is n2 and that of n numbers is m2, then the average of (m+n).
Sol. According to question
sum of n numbers = m*n2 = mn2
Sum of n numbers = n*m2 = nm2
(mn2 + nm2)/ m+n
mn(m+n)/m+n = mn Ans.
Ex.2 The average of three numbers is 28. The first number is half of the second number and the third number is twice the second. Find the third number.
Sol. Let the first number be = x
So the second number = 2x
third number = 4x
Total = x+2x+4x = 28*3
7x = 28*3
x=12
Third number is 4x = 48 Ans
Ex.3 Out of three numbers, the first is twice the second number and half of the third number, If the average of all the three numbers is 56 the difference between the first and third numbers is.
Sol. Let the first number = 2x
Second number = x
Third number = 4x
Total of three numbers = 2x +x +4x = 56 * 3
7x = 56*3
x = 8*3
x= 24
Difference between first and third number is
4x-2x = 2x = 48 Ans
Ex.4 There were 24 students in a class. One of them who was 18 years old left the class and his place was filled up by a new student. If the average of the class was therefore lowered by 1 month the age of the new students is.
Sol. Let the previous average be = x
Let the age of new student = y
So,
24x - 18 + y = 24(x - 1/12)
24x - 18 + y = 24x - 24 *1/12
-18 + y = -2
y = 16 years Ans
Method 2
18 - (24*1)/12 = 16 years Ans
Ex.5 The average of six numbers is 3.95. The average of two of them is 3.4 while the average of the other two is 3.85, the average of the remaining two numbers is.
Sol. [(3.95 *6 ) -(3.4*2 +3.85*2)]/2
[23.70 - (6.80 + 7.70)]
9.2/2 = 4.6 Ans
Ex.6 Out of 9 persons, 8 people spent Rs. 30 each for their meal. The 9th person spent Rs. 20 more than the average expenditure of all the 9 people, the total money spent by all of them was.
Sol. Let the average of nine person be x
So, total = 9x = 30*3 +x+20
8x = 260
x= 260/8 = 65/2
65/2 *9 = 292.5 Ans.
Method 2
Since 9th person spent 20 Rs. More
share of each person = 30 + 20/8 =32.5
Total expenditure = 292.5 Ans
Ex.7 In a school with 600 students the average age of boys is 12 years and that of girls is 11 years. If the average of the school is 11 years and 9 months, then the number of girls in the school.
Sol. Let the number of boys = x
So, the girls = 600 -x
According to the question
12x + 11(600-x) = 600* 11 years 9 months
23x +6600 - 11x = 600 * 11 9⁄12
x = 7050 - 6600
x = 450
Girls = 600-450 = 150 Ans
1:2:3 Ans
Ex.8 What is the average square of the natural numbers from 1 to 41.
Sol. Average of square of the natural numbers
(n+1)(2n+1)/6 = [(41+1)(2*41 +1)]/6
42*83/6 = 3486/6 = 581 Ans
Ex.9 A train covers 50% of the journey at 30 Km/hr, 25% of the journey at 25 km.her. and the remaining at 20 km/hr. find the average speed of the train during the entire journey.
Sol. Average speed = 100/ (A/x + b/y + c/z)
A = 50 B = 25 and C = 25
x= 30 y= 25 and c = 20
100/(50/30 + 25/25 + 25/20)
=1200/47 Ans
Ex.10 If the mean of a,b,c is M and ab+bc+ca =0 then the mean of a2,b2,c2 is.
Sol. Average of a,b,c is m
Total = (a+b+c)/3 = m
a+b+c = 3m
on squaring both sides
a2+b2+c2+ 2(ab+bc+ca) = 9m2
so the average of a2,b2,c2 is
(a2+b2+c2)/3 = 9m2/3 = 3m2 Ans
Ex.11 A batsman has a certain average of runs in 12 innings he scores 96 runs, thereby increasing his average by 5 runs. What is his average after the 13th inning?
Sol. Let the average of 12 innings be x
So, (12x + 96) /13
12x + 96 = 13x + 65
x = 31
the new average is x+5
31+5 = 36 Ans
Ex.12 a,b,c,d,e are five consecutive odd numbers their average is?
Sol. for odd number
the average = 1st step + (n-1)
Where n is number of step
a + (5-1) = a+4
a+4 Ans